poj 2503 map应用 与 C 输入问题

Babelfish

Time Limit: 3000MS		Memory Limit: 65536K
Total Submissions: 41067		Accepted: 17494

Description
You have just moved from Waterloo to a big city. The people here speak an incomprehensible dialect of a foreign language. Fortunately, you have a dictionary to help you understand them.
Input
Input consists of up to 100,000 dictionary entries, followed by a blank line, followed by a message of up to 100,000 words. Each dictionary entry is a line containing an English word, followed by a space and a foreign language
word. No foreign word appears more than once in the dictionary. The message is a sequence of words in the foreign language, one word on each line. Each word in the input is a sequence of at most 10 lowercase letters.
Output
Output is the message translated to English, one word per line. Foreign words not in the dictionary should be translated as "eh".

Sample Input

dog ogday
cat atcay
pig igpay
froot ootfray
loops oopslay

atcay
ittenkay
oopslay

Sample Output

cat
eh
loops

Hint
Huge input and output,scanf and printf are recommended.

题目大意：

将右端的单词翻译成左端的单词，如果字典中没有，则输出eh。

分析：

用map解决配对问题

while(gets(str))            //输入一行字符串

    {

        if(strcmp(str,"\0")==0) break;

        sscanf(str,"%s %s",str1,str2);     //  只读取不输入，读取 str 中 两个被空格隔开的字符串 给str1，str2         

    }

#include <iostream>
#include <cstdio>
#include <cstring>
#include <cstdlib>
#include <map>
using namespace std;

int main()
{
map<string,string> m;
char str1[50],str2[50],str[101];
while(gets(str))
{
if(strcmp(str,"\0")==0) break;
sscanf(str,"%s %s",str1,str2);
m.insert(pair<char *,char *>(str2,str1));
}
map<string,string>::iterator it=m.begin();

while(gets(str))
{
if(m.find(str)!=m.end())
printf("%s\n",m[str].c_str());
else
printf("eh\n");
}

return 0;
}