从键盘输入10个数字，进行冒泡排序

package Ex1;

/**
* Created by xukui on 2016/8/19.
**/

import java.util.Scanner;

public class Bubble_Sort {
public static void main(String[] args) {
double[] list = new double[10];
Scanner s = new Scanner(System.in);
System.out.println("请输入10个数字进行冒泡排序\n(注：每输完一个数字，请按Enter键输入下一个数字)");
for (int i = 0; i < 10; i++) {
System.out.print("请输入第 " + (i + 1) + " 个数字：");
list[i] = s.nextDouble();
}
System.out.println("您输入的数字是：");
for (double x : list) {
System.out.print(x + "\t");
}
System.out.println("\n-------------------------------------");

System.out.println("开始冒泡排序：");
for (int j = 0; j < list.length - 1; j++) {
boolean changed = false;
for (int k = 0; k < list.length - 1 - j; k++) {
if (list[k] < list[k + 1]) {
double temp = list[k + 1];
list[k + 1] = list[k];
list[k] = temp;
changed = true;
}
}
String s1 = String.format("第 %s 次的结果： ", j + 1);
System.out.print(s1);

for (double y : list) {
System.out.print(y + "\t");
}
System.out.println();

if (!changed) {
System.out.println("排序提前结束");
break;
}
}

System.out.println("-------------------------------------");
System.out.println("结果： ");
for (double z : list) {
System.out.print(z + "\t");
}
}
}