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合并两个排序的链表

2016-08-15 18:07 218 查看
#include<stdio.h>
#include<stdlib.h>
#include<string.h>

struct Node{
int m_value;
Node *m_next;
};
//递归方式
Node* Merge(Node* pHead1,Node* pHead2){
if(pHead1==NULL)
return pHead2;
elseif(pHead2==NULL)
return pHead1;
Node *Mergelist = NULL;
if(pHead1->m_value>=pHead2->m_value){
Mergelist = pHead1;
Mergelist->m_next = Merge(pHead1->m_next,pHead2);
}else{
Mergelist = pHead2;
Mergelist->m_next = Merge(pHead1,pHead2->m_next);
}
return Mergelist;
}
//非递归
Node*  noMerge(Node *pHead1,Node *pHead2){
if(pHead1==NULL) return pHead2;
if(pHead2==NULL) return pHead1;
Node* mergelist = NULL;
while(pHead1->m_next!=NULL&&pHead2->m_next!=NULL){
if(pHead1->m_value>=pHead2->m_value){
if(mergelist==NULL) mergelist = pHead1;
else  mergelist->m_next = pHead1;
pHead1 = pHead1->m_next;
}else{
if(mergelist==NULL) mergelist = pHead2;
else  mergelist->m_next = pHead2;
pHead2 = pHead2->m_next;
}
}
return mergelist;
}
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