Longest Palindromic Substring_Leetcode_#5
2016-08-13 09:56
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1.题目
Given a string S, find the longest palindromic substring in S. You may assume that the maximum length of S is 1000, and there exists one unique longest palindromic substring.
2.解法
思路:从数组开始处作为起点,并跳过与起点处值相等的位置;向前后两边扩散,如果前后两个位置字符相等,向外扩展;遇到前后两个位置处的值不相等的时候结束本轮遍历,并更新最大回文长度max_len和最大的起始点max_left.
时间复杂度为O(N^2)
Given a string S, find the longest palindromic substring in S. You may assume that the maximum length of S is 1000, and there exists one unique longest palindromic substring.
2.解法
思路:从数组开始处作为起点,并跳过与起点处值相等的位置;向前后两边扩散,如果前后两个位置字符相等,向外扩展;遇到前后两个位置处的值不相等的时候结束本轮遍历,并更新最大回文长度max_len和最大的起始点max_left.
时间复杂度为O(N^2)
public class Solution { public String longestPalindrome(String s) { int len = s.length(); if(len < 2){ return s; } int max_len = 1, max_left = 0, left, right; for(int start = 0; start < len && len - start > max_len / 2;){ left = right = start; while(right < len - 1 && s.charAt(right) == s.charAt(right+1)) ++right; start = right + 1; while(right < len - 1 && left > 0 && s.charAt(right + 1) == s.charAt(left - 1)){ --left; ++right; } if(max_len < right - left + 1){ max_len = right - left + 1; max_left = left; } } return s.substring(max_left, max_left + max_len); } }
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