Codeforces Round #367 (Div. 2) B. Interesting drink 树状数组

B. Interesting drink

time limit per test
2 seconds

memory limit per test
256 megabytes

input
standard input

output
standard output

Vasiliy likes to rest after a hard work, so you may often meet him in some bar nearby. As all programmers do, he loves the famous drink "Beecola", which can
be bought in n different shops in the city. It's known that the price of one bottle in the shop i is
equal to xi coins.

Vasiliy plans to buy his favorite drink for q consecutive days. He knows, that on the i-th
day he will be able to spent mi coins.
Now, for each of the days he want to know in how many different shops he can buy a bottle of "Beecola".

Input

The first line of the input contains a single integer n (1 ≤ n ≤ 100 000) —
the number of shops in the city that sell Vasiliy's favourite drink.

The second line contains n integers xi (1 ≤ xi ≤ 100 000) —
prices of the bottles of the drink in the i-th shop.

The third line contains a single integer q (1 ≤ q ≤ 100 000) —
the number of days Vasiliy plans to buy the drink.

Then follow q lines each containing one integer mi (1 ≤ mi ≤ 109) —
the number of coins Vasiliy can spent on the i-th day.

Output

Print q integers. The i-th
of them should be equal to the number of shops where Vasiliy will be able to buy a bottle of the drink on the i-th day.

Example

input

5
3 10 8 6 11
4
1
10
3
11

output

0
4
1
5

Note

On the first day, Vasiliy won't be able to buy a drink in any of the shops.

On the second day, Vasiliy can buy a drink in the shops 1, 2, 3 and 4.

On the third day, Vasiliy can buy a drink only in the shop number 1.

Finally, on the last day Vasiliy can buy a drink in any shop.

树状数组模版题，用二分也能做

下面代码：

#include <iostream>
#include <cmath>
#include <cstring>
#include <cstdlib>
#include <algorithm>
#include <cstdio>
#include <vector>
#include <map>
using namespace std;
const int maxn = 1e5+5;
int shop[maxn];
int c[maxn];
int lowbit(int x){
return x&(-x);
}
void update(int x,int val){
while(x<=maxn){
c[x] += val;
x += lowbit(x);
}
}
int getsum(int x){
int sum=0;
while(x>0){
sum += c[x];
x -=lowbit(x);
}
return sum;
}
int main(){
int n,i,j,q;
scanf("%d",&n);
memset(shop, 0, sizeof(shop));
for(i=1;i<=n;i++){
scanf("%d",&shop[i]);
update(shop[i], 1);
}
scanf("%d",&q);
int pay;
for(i=1;i<=q;i++){
int result =0;
scanf("%d",&pay);
if(pay>maxn){
pay=maxn-3;
}
result += getsum(pay);
printf("%d\n",result);
}
return 0;
}