leetcode题1Two sum 练习

Given nums = [2, 7, 11, 15], target = 9,

Because nums[0] + nums[1] = 2 + 7 = 9,
return [0, 1].

public int[] TwoSum(int[] nums, int target) {
int[] result=new int[2];//创建一个返回数组；

for (int j = 0; j < nums.Length; j++)//{1,4,5,7,9,10};//{9,6,5,3,1,0}外层循环，传进的数组赋值
{
for (int k = j+1; k < nums.Length; k++)//创建内层循环，内层循环主要是让temp[i]=target-nums[i];让temp[i]的值与数组nums[i]比自己大的元素比较看是否相等。
{

if (target - nums[j] == nums[k])
{

result[0] = j;//相等就记录该位置。
result[1] = k;//记录相等的位置。
}

}
}

return result;
}

namespace ConsoleApplication1
{
class addtwonum
{
public static void Main(string[] args)
{
int[] num = { 2, 4, 4, 4, 4, 10 };//{9,6,5,3,1,0}
int[] result = getnum(num, 8);
for (int i = 0; i < result.Length; i++)
{
Console.WriteLine(result[i]);
}
Console.ReadLine();
}
//
//{1,2,3,4,6} tagart =5
//a[0]+a[3] ,a[1]+a[2] [0,3],[1,2]
private static int[] getnum(int []nums,int tagart)
{
int[] result=new int[2];
int[] temp=new int[nums.Length];
//for (int i = 0; i < nums.Length; i++)
//    temp[i] = tagart - nums[i];
for (int j = 0; j < nums.Length; j++)//{2, 4, 4, 7, 9, 10};//{6,4,4,-1,-2,-3}|{7,5,5,2,0,-1}
{
for (int k = j+1; k < nums.Length; k++)
{
//result[0] = j;
//result[1] = k;
if (tagart - nums[j] == nums[k])
{
//j = nums.Length - 1;
//k = nums.Length;
result[0] = j;
result[1] = k;
}

}
}

return result;
}

}
}