hdu 1547 Bubble Shooter(DFS)
2016-08-05 17:43
288 查看
Bubble Shooter
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 1059 Accepted Submission(s): 455
Problem Description
Bubble shooter is a popular game. You can find a lot of versions from the Internet.
The goal of this game is to clean the bubbles off the field. Every time you just point the cannon to where you want the next bubble to go, and if three or more of bubbles with the same color came together (including the newly shot bubble), they will detonate.
After the first explode, if some bubbles are disconnected from the bubble(s) in the topmost row, they will explode too.
In this problem, you will be given an arranged situation of bubbles in the field and the newly shot bubble. Your program should output the total number of bubbles that will explode.
Input
There are multiple test cases. Each test case begins with four integers H (the height of the field, 2 <= H <= 100), W (the width of the field, 2 <= W <= 100, in the picture above, W is 10), h (the vertical position of the newly shot bubble, count from top to
bottom, and the topmost is counted as 1) and w (the horizontal position of the newly shot bubble, count from left to right, and the leftmost is counted as 1).
Then H lines follow, the odd lines will contain W characters while the even lines will contain W-1 characters (refer to the picture above). Each character will be either a lowercase from 'a' to 'z' indicating the color of the bubble in that position, or a capital
letter 'E' indicating an empty position. You may assure the arranged situation is always valid (all the bubbles are directly or indirectly connected with at least one bubble in the topmost row, and the position of newly shot bubble is never empty).
Output
For each test case, output an integer indicating how many bubbles will explode.
Sample Input
2 2 2 1
aa
a
3 3 3 3
aaa
ba
bba
3 3 3 1
aaa
ba
bba
3 3 3 3
aaa
Ea
aab
Sample Output
3
8
3
0
题意:泡泡龙游戏,注意一开始要用三个一样的泡泡才能消,是六个方向不是八个方向
思路:先用一次DFS去标记所有能达到的相同颜色的球,然后从天花板开始往下面搜索,把能标到的也标记成-1,最后把全部的球扫一遍,不是-1的就计数
最后输出即可
代码:
#include <iostream>
#include <cstdio>
#include <cstring>
#include <algorithm>
#include <cmath>
using namespace std;
#define N 150
char a
,ma
[2*N];
int vis
[2*N];
int n,m,x2,y2;
int dir[6][2]= {-1,-1,-1,1,0,-2,0,2,1,-1,1,1};
int flag;
int check(int x,int y)
{
if(x<1||x>n||y<1||y>2*m) return 0;
if(ma[x][y]=='A'||ma[x][y]=='E') return 0;
return 1;
}
void dfs(int u,int v)
{
vis[u][v]=-1;
for(int i=0; i<6; i++)
{
int x=u+dir[i][0],y=v+dir[i][1];
if(!check(x,y)||vis[x][y]) continue;
dfs(x,y);
}
}
void check1(int u,int v,int d)
{
vis[u][v]=1;
if(d>=2) flag=1;
for(int i=0; i<6; i++)
{
int x=u+dir[i][0],y=v+dir[i][1];
if(!check(x,y)||vis[x][y]) continue;
if(ma[x][y]==ma[u][v])
check1(x,y,d+1);
}
}
int main()
{
while(~scanf("%d %d %d %d",&n,&m,&x2,&y2))
{
for(int i=1; i<=n; i++)
scanf("%s",a[i]+1);
for(int i=1; i<=n; i++)
{
if(i&1)
{
int cnt=1;
for(int j=1; j<=m; j++)
{
ma[i][cnt]=a[i][j];
ma[i][cnt+1]='A';
cnt+=2;
}
}
else
{
int cnt=2;
ma[i][1]='A';
for(int j=1; j<m; j++)
{
ma[i][cnt]=a[i][j];
ma[i][cnt+1]='A';
cnt+=2;
}
for(int j=1; j<=3; j++)
ma[i][cnt++]='A';
}
}
if(x2&1) y2=(y2-1)*2+1;
else y2*=2;
flag=0;
memset(vis,0,sizeof(vis));
check1(x2,y2,0);
if(!flag)
{
printf("0\n");
continue;
}
for(int i=1; i<=2*m; i++)
if(ma[1][i]>='a'&&ma[1][i]<='z'&&!vis[1][i])
dfs(1,i);
int ans=0;
for(int i=1;i<=n;i++)
for(int j=1;j<=2*m;j++)
if(ma[i][j]>='a'&&ma[i][j]<='z'&&vis[i][j]!=-1)
ans++;
printf("%d\n",ans);
}
return 0;
}
相关文章推荐
- hdu 1547 Bubble Shooter
- HDU 1547 Bubble Shooter(BFS)
- HDU 1547 Bubble Shooter BFS
- HDU 1547 Bubble Shooter
- HDU 1547 Bubble Shooter(BFS蔓延模拟)
- HDU-1547 Bubble Shooter 搜索
- hdu 1547 Bubble Shooter(深搜)
- hdoj 1547 Bubble Shooter(dfs+dfs)
- hdu 5546 Ancient Go(dfs)
- HDU 1015 Safecracker (很棒的一道DFS)
- hdu 5834 dfs
- HDU 1010 Tempter of the Bone(DFS+奇偶剪枝)
- hdu 4771 Stealing Harry Potter's Precious(DFS+BFS)
- hdu 1254 推箱子(嵌套搜索,bfs中有dfs)
- hdu变形课(dfs)
- hdu 2874 Connections between cities LCA || dfs+并查集
- HDU 5305 Friends dfs
- hdu 4770 Lights Against Dudely(暴力枚举dfs)
- HDU 1428 漫步校园(BFS+DFS)
- POJ-1979&&HDU-1312--Red and Black---DFS深搜