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HDU 2689 Sort it

2016-08-01 14:26 369 查看
求逆序数。分治写法。

#pragma comment(linker, "/STACK:1024000000,1024000000")
#include<cstdio>
#include<cstring>
#include<cmath>
#include<algorithm>
#include<vector>
#include<map>
#include<set>
#include<queue>
#include<stack>
#include<iostream>
using namespace std;
typedef long long LL;
const double pi=acos(-1.0),eps=1e-8;
void File()
{
freopen("D:\\in.txt","r",stdin);
freopen("D:\\out.txt","w",stdout);
}
inline int read()
{
char c = getchar();  while(!isdigit(c)) c = getchar();
int x = 0;
while(isdigit(c)) { x = x * 10 + c - '0'; c = getchar(); }
return x;
}

int n,a[1010];

int get(int l,int r,vector<int> &b)
{
if(l==r) { b.push_back(a[l]); return 0; }
int m=(l+r)/2; vector<int>L,R;
int x1=get(l,m,L), x2=get(m+1,r,R);
int x3=0,pl=0,pr=0;
for(;;)
{
if(pl==L.size()&&pr==R.size()) break;
if(pl<L.size()&&pr<R.size())
{
if(L[pl]<R[pr]) b.push_back(L[pl++]);
else b.push_back(R[pr++]), x3=x3+L.size()-pl;
}
else if(pl<L.size()&&pr==R.size()) b.push_back(L[pl++]);
else if(pl==L.size()&&pr<R.size()) b.push_back(R[pr++]), x3=x3+L.size()-pl;
}
return x1+x2+x3;
}

int main()
{
while(~scanf("%d",&n))
{
for(int i=1;i<=n;i++) scanf("%d",&a[i]);
vector<int> f; printf("%d\n",get(1,n,f));
}
return 0;
}
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