51Nod－1283－最小周长

描述

题解

int

cout

double

代码

#include <iostream>
#include <cstdio>
#include <cmath>

using namespace std;

int main(int argc, const char * argv[])
{
int S;
while (cin >> S)
{
double s = sqrt(S);
for (int i = (int)s; i > 0; i--)
{
double res = S * 1.0 / i;
if (res == (int)res)
{
int ans = i + i + res + res;    //  cout << i + i + res + res << '\n';如此会WA，需要将结果格式化
printf("%d\n", ans);
break;
}
}
}

return 0;
}