Educational Codeforces Round 15 套题
2016-07-30 15:54
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这套题最后一题不会,然后先放一下,最后一题应该是大数据结构题
A:求连续最长严格递增的的串,O(n)简单dp
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F:不会,看了看别人的代码,并不能看懂,还是太弱
A:求连续最长严格递增的的串,O(n)简单dp
#include <cstdio> #include <cstdlib> #include <cstring> #include <cmath> #include <iostream> #include <algorithm> #include <map> #include <queue> #include <vector> using namespace std; typedef long long LL; const int N = 1e5+5; const int INF = 2e9; struct Node{ int v,mn; LL sum; }f [40]; LL retsum ,k; int n,retmin ,cur ; void solve(){ for(int j=0;(1ll<<j)<=k;++j)if(k&(1ll<<j)){ for(int i=0;i<n;++i){ retsum[i]+=f[cur[i]][j].sum; if(retmin[i]==-1)retmin[i]=f[cur[i]][j].mn; else retmin[i]=min(retmin[i],f[cur[i]][j].mn); cur[i]=f[cur[i]][j].v; } } for(int i=0;i<n;++i) printf("%I64d %d\n",retsum[i],retmin[i]); } int main(){ scanf("%d%I64d",&n,&k); for(int i=0;i<n;++i)scanf("%d",&f[i][0].v),cur[i]=i,retmin[i]=-1; for(int i=0;i<n;++i)scanf("%d",&f[i][0].mn),f[i][0].sum=f[i][0].mn; for(int j=1;(1ll<<j)<=k;++j){ for(int i=0;i<n;++i){ f[i][j].v=f[f[i][j-1].v][j-1].v; f[i][j].sum=f[i][j-1].sum+f[f[i][j-1].v][j-1].sum; f[i][j].mn=min(f[i][j-1].mn,f[f[i][j-1].v][j-1].mn); } } solve(); return 0; }
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F:不会,看了看别人的代码,并不能看懂,还是太弱
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