uva 10361
2016-07-23 23:10
429 查看
一道水水的题。注意的地方就是对字符串顺序处理时每个s串进行正确的分配,注意好边界问题就可以了。另外就是在进行测试用例之前注意好变量的初始化。
code:
code:
#include <iostream> #include <stdio.h> #include <stdlib.h> #include <string> #include <string.h> using namespace std; int n; char ch; string s[6], strone, strtwo, secondline; void read() { for (int i = 0; i <= 5; i++) s[i].clear(); secondline.clear(); while ((ch = getchar()) != '\n') s[0] += ch; while ((ch = getchar()) != '\n' && (ch != EOF)) secondline += ch; int fpos1 = 0, spos1 = 0, fpos2, spos2; fpos1 = s[0].find('<'); s[1] = s[0].substr(0, fpos1); spos1 = s[0].find('>'); for (int i = fpos1 + 1; i < spos1; i++) s[2] += s[0][i]; fpos2 = s[0].find('<', spos1); for (int i = spos1 + 1; i < fpos2; i++) s[3] += s[0][i]; spos2 = s[0].find('>', fpos2); for (int i = fpos2 + 1; i < spos2; i++) s[4] += s[0][i]; for (int i = spos2 + 1; i < s[0].length(); i++) s[5] += s[0][i]; } int main() { freopen("in.txt", "r", stdin); freopen("out.txt", "w", stdout); scanf("%d", &n); getchar(); while (n--) { read(); for (int i = 1; i <= 5; i++) cout << s[i]; cout << endl; cout << secondline.substr(0, secondline.length() - 3); cout << s[4] << s[3] << s[2] << s[5] << endl; } return 0; }