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uva 10361

2016-07-23 23:10 429 查看
一道水水的题。注意的地方就是对字符串顺序处理时每个s串进行正确的分配,注意好边界问题就可以了。另外就是在进行测试用例之前注意好变量的初始化。

code:

#include <iostream>
#include <stdio.h>
#include <stdlib.h>
#include <string>
#include <string.h>

using namespace std;

int n;
char ch;
string s[6], strone, strtwo, secondline;

void read()
{
for (int i = 0; i <= 5; i++)
s[i].clear();
secondline.clear();

while ((ch = getchar()) != '\n')
s[0] += ch;
while ((ch = getchar()) != '\n' && (ch != EOF))
secondline += ch;

int fpos1 = 0, spos1 = 0, fpos2, spos2;
fpos1 = s[0].find('<');
s[1] = s[0].substr(0, fpos1);
spos1 = s[0].find('>');
for (int i = fpos1 + 1; i < spos1; i++)
s[2] += s[0][i];

fpos2 = s[0].find('<', spos1);
for (int i = spos1 + 1; i < fpos2; i++)
s[3] += s[0][i];
spos2 = s[0].find('>', fpos2);
for (int i = fpos2 + 1; i < spos2; i++)
s[4] += s[0][i];

for (int i = spos2 + 1; i < s[0].length(); i++)
s[5] += s[0][i];
}

int main()
{
freopen("in.txt", "r", stdin);
freopen("out.txt", "w", stdout);
scanf("%d", &n);
getchar();
while (n--)
{
read();
for (int i = 1; i <= 5; i++)
cout << s[i];
cout << endl;
cout << secondline.substr(0, secondline.length() - 3);
cout << s[4] << s[3] << s[2] << s[5] << endl;
}
return 0;
}
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