HDU 5655 CA Loves Stick（思维题目）【bestcoder】

CA Loves Stick

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 262144/262144 K (Java/Others)

Total Submission(s): 2130    Accepted Submission(s): 615


Problem Description

CA loves to play with sticks.

One day he receives four pieces of sticks, he wants to know these sticks can spell a quadrilateral.

(What is quadrilateral? Click here: https://en.wikipedia.org/wiki/Quadrilateral)
 

Input

First line contains T denoting
the number of testcases.
T testcases
follow. Each testcase contains four integers a,b,c,d in
a line, denoting the length of sticks.
1≤T≤1000, 0≤a,b,c,d≤263−1

 

Output

For each testcase, if these sticks can spell a quadrilateral, output "Yes"; otherwise, output "No" (without the quotation marks).

 

Sample Input

2
1 1 1 1
1 1 9 2

 

Sample Output

Yes
No

 
本题的题意就是给你四根木棒，然后问你能不能组成四边形，四边形的定义上面已经给出。
很明显需要满足最小的三条边之和大于第四条边，而且最小的边不能为0 。
直接加的话会爆long long ，所以我们需要转换一下思路，就是最小的边大于最长的边减去另外两条边的长度。
下面是AC代码：

#include<cstdio>
#include<cstring>
#include<algorithm>
using namespace std;
#define ll long long

ll a[4];

int main()
{
int t;
scanf("%d",&t);
while(t--)
{
scanf("%I64d %I64d %I64d %I64d",&a[0],&a[1],&a[2],&a[3]);
sort(a,a+4);
if(a[0]==0)
{
printf("No\n");
continue;
}
if(a[0]>a[3]-a[2]-a[1])
{
printf("Yes\n");
}
else
{
printf("No\n");
}
}
return 0;
}