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HDU 5733 tetrahedron

2016-07-22 08:50 232 查看
计算几何。先判四点是否共面,共面则无解。然后计算出圆心坐标,然后计算圆心到任意一面的距离。

#include<cstdio>
#include<cstring>
#include<cmath>
#include<algorithm>
#include<vector>
#include<map>
#include<set>
#include<queue>
#include<stack>
#include<iostream>
using namespace std;
typedef long long LL;

#define eps 1e-8
#define zero(x) (((x)>0?(x):-(x))<eps)
struct point3
{
double x,y,z;
};
struct line3
{
point3 a,b;
};
struct plane3
{
point3 a,b,c;
};

//计算 cross product product product product U x V
point3 xmult(point3 u,point3 v)
{
point3 ret;
ret.x=u.y*v.z-v.y*u.z;
ret.y=u.z*v.x-u.x*v.z;
ret.z=u.x*v.y-u.y*v.x;
return ret;
}
//计算 dot product product product product U . V
double dmult(point3 u,point3 v)
{
return u.x*v.x+u.y*v.y+u.z*v.z;
}
//矢量差 U - V
point3 subt(point3 u,point3 v)
{
point3 ret;
ret.x=u.x-v.x;
ret.y=u.y-v.y;
ret.z=u.z-v.z;
return ret;
}
//取平面法向量
point3 pvec(plane3 s)
{
return xmult(subt(s.a,s.b),subt(s.b,s.c));
}
point3 pvec(point3 s1,point3 s2,point3 s3)
{
return xmult(subt(s1,s2),subt(s2,s3));
}
//两点距离,单参数取向量大小
double dis(point3 p1,point3 p2)
{
return sqrt((p1.x-p2.x)*(p1.x-p2.x)+(p1.y-p2.y)*(p1.y-p2.y)+(p1.z-p2.z)*(p1.z-p2.z));
}
//向量大小
double vlen(point3 p)
{
return sqrt(p.x*p.x+p.y*p.y+p.z*p.z);
}

int dots_onplane(point3 a,point3 b,point3 c,point3 d)
{
return zero(dmult(pvec(a,b,c),subt(d,a)));
}

//点到平面距离
double ptoplane(point3 p,point3 s1,point3 s2,point3 s3)
{
return fabs(dmult(pvec(s1,s2,s3),subt(p,s1)))/vlen(pvec(s1,s2,s3));
}

double Area(point3 a,point3 b,point3 c)
{
double ab=dis(a,b),bc=dis(b,c),ac=dis(a,c);
double p=(ab+bc+ac)/2;
return sqrt(p* (p-ab) * (p-bc)*(p-ac));
}

int main()
{
point3 p[5];
while(~scanf("%lf%lf%lf",&p[1].x,&p[1].y,&p[1].z))
{
for(int i=2;i<=4;i++) scanf("%lf%lf%lf",&p[i].x,&p[i].y,&p[i].z);
if(dots_onplane(p[1],p[2],p[3],p[4])) { printf("O O O O\n"); continue; }
double Sabc=Area(p[1],p[2],p[3]);
double Sabd=Area(p[1],p[2],p[4]);
double Sacd=Area(p[1],p[3],p[4]);
double Sbcd=Area(p[2],p[3],p[4]);
double S=Sabc+Sabd+Sacd+Sbcd;
point3 heart;
heart.x=( Sabc*p[4].x+Sabd*p[3].x + Sacd*p[2].x+Sbcd*p[1].x)/S;
heart.y=( Sabc*p[4].y+Sabd*p[3].y + Sacd*p[2].y+Sbcd*p[1].y)/S;
heart.z=( Sabc*p[4].z+Sabd*p[3].z + Sacd*p[2].z+Sbcd*p[1].z)/S;
printf("%.4lf %.4lf %.4lf %.4lf\n",heart.x,heart.y,heart.z,ptoplane(heart,p[1],p[2],p[3]));
}
return 0;
}
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