您的位置:首页 > 其它

【Leetcode】之Gray Code

2016-07-21 23:05 393 查看

一.问题描述

The gray code is a binary numeral system where two successive values differ in only one bit.

Given a non-negative integer n representing the total number of bits in the code, print the sequence of gray code. A gray code sequence must begin with 0.

For example, given n = 2, return 
[0,1,3,2]
. Its gray code sequence
is:
00 - 0
01 - 1
11 - 3
10 - 2


Note:

For a given n, a gray code sequence is not uniquely defined.

For example, 
[0,2,3,1]
 is also a valid gray code sequence according to the above definition.

For now, the judge is able to judge based on one instance of gray code sequence. Sorry about that.


二.我的解题思路

拿到题目观察一番,就不难想到可以用分治递归的算法思想去解决。具体实现起来也比较容易,测试通过的程序如下:
class Solution {
public:
vector<int> grayCode(int n) {
vector<int> res(pow(2.0,n),0);
if(n<=0) return res;
gen_code(res,n);
return res;
}

void gen_code(vector<int>& res,int n){
if(n==1){
res[0]=0;
res[1]=1;
return;
}
int curr_num=pow(2.0,n-1);
gen_code(res,n-1);
for(int i=curr_num;i<2*curr_num;i++){
res[i]=pow(2.0,n-1)+res[2*curr_num-i-1];
}
}
};
内容来自用户分享和网络整理,不保证内容的准确性,如有侵权内容,可联系管理员处理 点击这里给我发消息
标签: