Leetcode 226:Invert a binary tree
2016-07-18 19:40
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Leetcode—226
Invert a binary tree.4 / \ 2 7 / \ / \ 1 3 6 9
to
4 / \ 7 2 / \ / \ 9 6 3 1
【题目大意】：反转二叉树
第一次在知乎看到这个题目背后的故事的时候觉得蛮惊奇的
【解法】：简单的二叉树遍历，后续遍历
【AC代码】：
/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* struct TreeNode *left;
* struct TreeNode *right;
* };
*/
struct TreeNode* invertTree(struct TreeNode* root) {
if(!root){
return NULL;
}
else{
struct TreeNode * rleft = invertTree(root -> left);
struct TreeNode * rright = invertTree(root -> right);
root ->left = rright;
root ->right = rleft;
return root;
}
}
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