您的位置:首页 > 其它

[Leetcode]58. Length of Last Word

2016-07-14 22:12 281 查看
Given a string s consists of upper/lower-case alphabets and empty space characters 
'
'
, return the length of last word in the string.

If the last word does not exist, return 0.

Note: A word is defined as a character sequence consists of non-space characters only.

For example, 

Given s = 
"Hello World"
,

return 
5
.

class Solution {
public:
int lengthOfLastWord(string s) {
auto first = find_if(s.rbegin(), s.rend(), ::isalpha);
auto last = find_if_not(first, s.rend(), ::isalpha);
return distance(first, last);
}
};
内容来自用户分享和网络整理,不保证内容的准确性,如有侵权内容,可联系管理员处理 点击这里给我发消息
标签:  leetcode