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【leetcode】372. Super Pow【M】【40】

2016-07-12 16:11 344 查看
Your task is to calculate ab mod 1337 where a is a positive integer and b is an extremely large positive integer
given in the form of an array.

Example1:
a = 2
b = [3]

Result: 8


Example2:
a = 2
b = [1,0]

Result: 1024


Credits:

Special thanks to @Stomach_ache for adding this problem and creating all test cases.

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对幂,每一位进行计算

需要注意的一个地方就是,每一位升到上一位的时候,是十次幂

class Solution(object):
def superPow(self, a, b):
a = a % 1337
res = a ** b[0] % 1337

for i in b[1:]:
res = res ** 10 * (a ** i) % 1337
res %= 1337

return res
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