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leetcode342. Power of Four

2016-07-02 16:39 585 查看
Given an integer (signed 32 bits), write a function to check whether it is a power of 4.

Example:

Given num = 16, return true. Given num = 5, return false.

Follow up: Could you solve it without loops/recursion?

x&(x-1)==0 ->x为2的幂

4的幂的1在奇数位上

class Solution(object):
def isPowerOfFour(self, num):
"""
:type num: int
:rtype: bool
"""
return num>0 and (num &(num-1))==0 and (num & 0x55555555) == num
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标签:  leetcode