您的位置:首页 > 产品设计 > UI/UE

TreeMap按value值进行排序

2016-06-27 09:51 501 查看
import java.util.ArrayList;

import java.util.Collections;

import java.util.Comparator;

import java.util.HashMap;

import java.util.LinkedHashMap;

import java.util.List;

import java.util.Map;

import java.util.TreeMap;

public class CountAccurrenceOfWord {
public static void main(String[] args) {
String text = "Have a good day. Have a good class. Have a good visit. Have fun";

Map<String, Integer> hashMap = new HashMap<String, Integer>();
String[] words = text.split("[ .!?]");
for (int i = 0; i < words.length; i++) {
if (words[i].length() > 1) {
if (hashMap.get(words[i]) != null) {
int value = hashMap.get(words[i]).intValue();
value++;
hashMap.put(words[i], value);
} else
hashMap.put(words[i], 1);

}
}

Map<String, Integer> treeMap = new TreeMap<String, Integer>(hashMap);
System.out
.println("Dispaly words and their count in ascending order of the word");
System.out.println(treeMap);

List arrayList = new ArrayList(hashMap.entrySet());
Collections.sort(arrayList, new Comparator(){
public int compare(Object o1, Object o2) {
Map.Entry obj1 = (Map.Entry) o1;
Map.Entry obj2 = (Map.Entry) o2;
return ((Integer) obj2.getValue()).compareTo((Integer)obj1.getValue());
}
});

System.out.println(arrayList);

  

}

}
内容来自用户分享和网络整理,不保证内容的准确性,如有侵权内容,可联系管理员处理 点击这里给我发消息
标签: