您的位置:首页 > 其它

leetcode 5. Longest Palindromic Substring

2016-06-25 17:30 423 查看
Given a string S, find the longest palindromic substring in S. You may assume that the maximum length of S is 1000, and there exists one unique longest palindromic substring.

找到一个字符串中的最长连续回文串.

以一个字符或两个字符为中心,向两边扩展找回文串.

public class A05LongestPalindromicSubstring_1 {
public String longestPalindrome(String s) {
int begin = 0, end = 1;
int len1, len2, len;
for(int i = 0; i < s.length(); i++) {
len1 = findPalindrome(s, i, i);
len2 = findPalindrome(s, i, i + 1);
len = Math.max(len1, len2);
if(len > end - begin) {
begin = i - (len - 1) / 2;
end = i + 1 + len / 2;
}
}
return s.substring(begin, end);
}

public int findPalindrome(String s, int left, int right) {
while(left >= 0 && right < s.length() && s.charAt(left) == s.charAt(right)) {
left--;
right++;
}
return right - left - 1;
}
}
内容来自用户分享和网络整理,不保证内容的准确性,如有侵权内容,可联系管理员处理 点击这里给我发消息
标签:  leetcode