Codeforces Round #359 (Div. 2) A. Free Ice Cream

题目链接：http://codeforces.com/contest/686/problem/A

A. Free Ice Cream

time limit per test
2 seconds

memory limit per test
256 megabytes

input
standard input

output
standard output

After their adventure with the magic mirror Kay and Gerda have returned home and sometimes give free ice cream to kids in the summer.

At the start of the day they have x ice cream packs. Since the ice cream is free, people start standing in the queue before Kay and
Gerda's house even in the night. Each person in the queue wants either to take several ice cream packs for himself and his friends or to give several ice cream packs to Kay and Gerda (carriers that bring ice cream have to stand in the same queue).

If a carrier with d ice cream packs comes to the house, then Kay and Gerda take all his packs. If a child who wants to take d ice
cream packs comes to the house, then Kay and Gerda will give him d packs if they have enough ice cream, otherwise the child will get
no ice cream at all and will leave in distress.

Kay wants to find the amount of ice cream they will have after all people will leave from the queue, and Gerda wants to find the number of distressed kids.

Input

The first line contains two space-separated integers n and x (1 ≤ n ≤ 1000, 0 ≤ x ≤ 109).

Each of the next n lines contains a character '+'
or '-', and an integer di,
separated by a space (1 ≤ di ≤ 109).
Record "+ di"
in i-th line means that a carrier with di ice
cream packs occupies i-th place from the start of the queue, and record "- di"
means that a child who wants to take di packs
stands in i-th place.

Output

Print two space-separated integers — number of ice cream packs left after all operations, and number of kids that left the house in distress.

Examples

input

5 7
+ 5
- 10
- 20
+ 40
- 20

output

22 1

input

5 17
- 16
- 2
- 98
+ 100
- 98

output

3 2

Note

Consider the first sample.

Initially Kay and Gerda have 7 packs of ice cream.

Carrier brings 5 more, so now they have 12 packs.

A kid asks for 10 packs and receives them. There are only 2 packs
remaining.

Another kid asks for 20 packs. Kay and Gerda do not have them, so the kid goes away distressed.

Carrier bring 40 packs, now Kay and Gerda have 42 packs.

Kid asks for 20 packs and receives them. There are 22 packs
remaining.

题意

一共有n个小孩，当前你手里有x块糖，如果接收加号那么你增加di块糖，如果接收减号，你需要判断自己的糖是否足够给第i个小孩，如果不够那么这个小孩不开心，并且一个都不给他，输出最后自己手里剩几块糖和不开心的小孩数量。

代码

#include <bits/stdc++.h>
using namespace std;
int main()
{
int n,i,a,count=0;
long long s;
int z[1005];
char h[1005][5];
cin>>n>>i;
s=i;
for(a=0;n>a;a++){
cin>>h[a]>>z[a];
if(h[a][0]=='-'){
if(s>=z[a]){
s-=z[a];
}
else{
count++;
}
}
else{
s+=z[a];
}
}
cout<<s<<" "<<count<<endl;
return 0;
}