第12周项目一(2)-实现复数中的运算符重载
2016-06-21 15:14
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* *烟台大学计算机学院 *文件名称:xiangmu1.cpp *作 者:李亚辉 *完成日期:2016年6月21日 *版 本 号:vc++6.0 * *问题描述: 定义一个完整的类,定义运算符功能,使之能与double型数据进行运算 *输入描述: 无 *程序输出: 无 .*/ #include <iostream> using namespace std; class Complex { public: Complex() { real=0; imag=0; } Complex(double r,double i) { real=r; imag=i; } friend Complex operator+(Complex &c1, Complex &c2); friend Complex operator+(double d1, Complex &c2); friend Complex operator+(Complex &c1, double d2); friend Complex operator-(Complex &c1, Complex &c2); friend Complex operator-(double d1, Complex &c2); friend Complex operator-(Complex &c1, double d2); friend Complex operator*(Complex &c1, Complex &c2); friend Complex operator*(double d1, Complex &c2); friend Complex operator*(Complex &c1, double d2); friend Complex operator/(Complex &c1, Complex &c2); friend Complex operator/(double d1, Complex &c2); friend Complex operator/(Complex &c1, double d2); void display(); private: double real; double imag; }; //复数相加:(a+bi)+(c+di)=(a+c)+(b+d)i. Complex operator+(Complex &c1, Complex &c2) { Complex c; c.real=c1.real+c2.real; c.imag=c1.imag+c2.imag; return c; } Complex operator+(double d1, Complex &c2) { Complex c(d1,0); return c+c2; //按运算法则计算的确可以,但充分利用已经定义好的代码,既省人力,也避免引入新的错误,但可能机器的效率会不佳 } Complex operator+(Complex &c1, double d2) { Complex c(d2,0); return c1+c; } //复数相减:(a+bi)-(c+di)=(a-c)+(b-d)i. Complex operator-(Complex &c1, Complex &c2) { Complex c; c.real=c1.real-c2.real; c.imag=c1.imag-c2.imag; return c; } Complex operator-(double d1, Complex &c2) { Complex c(d1,0); return c-c2; } Complex operator-(Complex &c1, double d2) { Complex c(d2,0); return c1-c; } //复数相乘:(a+bi)(c+di)=(ac-bd)+(bc+ad)i. Complex operator*(Complex &c1, Complex &c2) { Complex c; c.real=c1.real*c2.real-c1.imag*c2.imag; c.imag=c1.imag*c2.real+c1.real*c2.imag; return c; } Complex operator*(double d1, Complex &c2) { Complex c(d1,0); return c*c2; } Complex operator*(Complex &c1, double d2) { Complex c(d2,0); return c1*c; } //复数相除:(a+bi)/(c+di)=(ac+bd)/(c^2+d^2) +(bc-ad)/(c^2+d^2)i Complex operator/(Complex &c1, Complex &c2) { Complex c; c.real=(c1.real*c2.real+c1.imag*c2.imag)/(c2.real*c2.real+c2.imag*c2.imag); c.imag=(c1.imag*c2.real-c1.real*c2.imag)/(c2.real*c2.real+c2.imag*c2.imag); return c; } Complex operator/(double d1, Complex &c2) { Complex c(d1,0); return c/c2; } Complex operator/(Complex &c1, double d2) { Complex c(d2,0); return c1/c; } void Complex::display() { cout<<"("<<real<<","<<imag<<"i)"<<endl; } int main() { Complex c1(3,4),c2(5,-10),c3; double d=11; cout<<"c1="; c1.display(); cout<<"c2="; c2.display(); cout<<"d="<<d<<endl<<endl; cout<<"下面是重载运算符的计算结果: "<<endl; c3=c1+c2; cout<<"c1+c2="; c3.display(); cout<<"c1+d="; (c1+d).display(); cout<<"d+c1="; (d+c1).display(); c3=c1-c2; cout<<"c1-c2="; c3.display(); cout<<"c1-d="; (c1-d).display(); cout<<"d-c1="; (d-c1).display(); c3=c1*c2; cout<<"c1*c2="; c3.display(); cout<<"c1*d="; (c1*d).display(); cout<<"d*c1="; (d*c1).display(); c3=c1/c2; cout<<"c1/c2="; c3.display(); cout<<"c1/d="; (c1/d).display(); cout<<"d/c1="; (d/c1).display(); return 0; } //学习心得:进一步学习并运用了运算符重载,感觉在运用友元函数,与不用友元函数时,有很多运用规则、形式发生不同,这是应该注意的点,在基类的基础上拓展其功能,也是对前面一些知识点的总结与运用。还是熟能生巧,感觉自己就是做的太少了,用起来很生涩,虽然老师每一个知识点都会有给的相应的项目进行训练,感觉自己还是做得太少了,果然实践才是硬道理啊。
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