您的位置:首页 > 其它

search in 2d matrix and serach minimum in rotated array

2016-06-19 22:53 309 查看
import java.io.*;
import java.lang.reflect.Array;
import java.util.Arrays;
import java.util.Collection;
class test
{
public static void main (String[] args) throws java.lang.Exception
{
int[] B = {6,7,8,9,1,2,3,4,5};
int[][] c = {{1,   3,  5,  7},{10, 11, 16, 20}, {23, 30, 34, 50}};

System.out.println(search_mini(B));
System.out.println(search(B,1));
System.out.println(Arrays.toString(search_2d_matrix(c,30)));
}

public static int[] search_2d_matrix(int[][] matrix, int target){
int row = matrix.length, column = matrix[0].length;
int begin = 0, end = row * column ;
int[] result = {-1, -1};

while (begin + 1 < end) {
int mid = (begin +  end) / 2;
int number = matrix[mid / column][mid % column];
if (number == target) {
result[0] = mid / column;
result[1] = mid % column;
return result;
} else if (number < target) {
begin = mid;
} else {
end = mid;
}
}
return result;
}

public static int search_mini(int[] A){
int begin = 0, end = A.length - 1;
while (begin < end && A[begin] >= A[end]) {
int mid = (begin + end) / 2;
if (A[mid] > A[end]) {
begin = mid + 1;
} else if (A[mid] < A[begin]) {
end = mid;
} else {   // A[begin] == A[mid] == A[end]
begin = begin + 1;
}
}
return A[begin];
}

public static int search(int[] A, int target){
int begin = 0;
int end = A.length ;
while(begin < end){
int p = (end + begin) / 2;
if(A[p] == target) return p;
else if(A[p] > A[begin]  ){
if(target >= A[begin] && target < A[p]){
end = p;
}
else begin = p + 1;
}
else{
if(target > A[p] && target <= A[end - 1] ){
begin = p + 1;
}
else end = p;
}

}
return -1;
}
}
内容来自用户分享和网络整理,不保证内容的准确性,如有侵权内容,可联系管理员处理 点击这里给我发消息
标签: