剑指offer（23）-二叉搜索树与双向链表

题目描述

代码

/*
struct TreeNode {
int val;
struct TreeNode *left;
struct TreeNode *right;
TreeNode(int x) :
val(x), left(NULL), right(NULL) {
}
};*/
class Solution {
public:
TreeNode* Convert(TreeNode* pRootOfTree)
{
if(pRootOfTree == NULL) return pRootOfTree;
pRootOfTree = ConvertNode(pRootOfTree);
while(pRootOfTree->left) pRootOfTree = pRootOfTree->left;
return pRootOfTree;
}

TreeNode* ConvertNode(TreeNode* root)
{
if(root == NULL) return root;
if(root->left)
{
TreeNode *left = ConvertNode(root->left);
while(left->right) left = left->right;
left->right = root;
root->left = left;
}

if(root->right)
{
TreeNode *right = ConvertNode(root->right);
while(right->left) right = right->left;
right->left = root;
root->right = right;
}
return root;
}
};