把数组排成最小的数

public String PrintMinNumber(int [] numbers){
for(int i = 0;i < numbers.length - 1; i ++) {
for(int j = 0;j < numbers.length - i - 1;j ++) {
int first = numbers[j];
int second = numbers[j + 1];
// 比较两个数
// 获取位数
char[] cArr1 = String.valueOf(first).toCharArray();
char[] cArr2 = String.valueOf(second).toCharArray();
for(int k = 0;k < cArr1.length || k < cArr2.length;k ++) {
int temp1 = 0,temp2 = 0;
if(k < cArr1.length)
temp1 = Integer.valueOf(cArr1[k]);
else
temp1 = Integer.valueOf(cArr1[cArr1.length - 1]);

if(k < cArr2.length)
temp2 = Integer.valueOf(cArr2[k]);
else
temp2 = Integer.valueOf(cArr2[cArr2.length - 1]);

if(temp2 <= temp1) {
int t = numbers[j];
numbers[j] = numbers[j + 1];
numbers[j + 1] = t;
break;
}
}
}
}

StringBuffer sb = new StringBuffer();
for(int number : numbers) {
sb.append(number);
}
return sb.toString();
}