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leecode_279 Perfect Squares

2016-06-10 06:30 330 查看
Given a positive integer n, find the least number of perfect square numbers (for example, 
1,
4, 9, 16, ...
) which sum to n.

For example, given n = 
12
, return 
3
 because 
12
= 4 + 4 + 4
; given n = 
13
, return 
2
 because 
13
= 4 + 9
.

bfs内存爆了,还是用dp吧

class Solution {
public:
int numSquares(int n) {
const int len=n+1;
int res[len];
for (int i=0;i<len;i++)
res[i]=INT_MAX;
for (int i=1;i*i<=n;i++)
res[i*i]=1;

for (int i=1;i<=n;i++) {

for (int j=1;j*j<=i;j++){
if (i+j*j>n)
break;
if (i+j*j<=n ){
res[i+j*j]=min(res[i]+1,res[i+j*j]);

}
}

}

// for (int i=1;i<=n;i++)
// cout<<i<<"("<<res[i]<<")"<<" ";
// cout<<endl;

return res
;

}
};
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