HDU--2052 picture
2016-06-07 13:07
211 查看
Total Submission(s): 23172 Accepted Submission(s): 11813
[align=left]Problem Description[/align]
Give you the width and height of the rectangle,darw it.
[align=left]Input[/align]
Input contains a number of test cases.For each case ,there are two numbers n and m (0 < n,m < 75)indicate the width and height of the rectangle.Iuput ends of EOF.
[align=left]Output[/align]
For each case,you should draw a rectangle with the width and height giving in the input.
after each case, you should a blank line.
[align=left]Sample Input[/align]
3 2
[align=left]Sample Output[/align]
+---+
| |
| |
+---+代码:
Picture
Time Limit: 1000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 23172 Accepted Submission(s): 11813
[align=left]Problem Description[/align]
Give you the width and height of the rectangle,darw it.
[align=left]Input[/align]
Input contains a number of test cases.For each case ,there are two numbers n and m (0 < n,m < 75)indicate the width and height of the rectangle.Iuput ends of EOF.
[align=left]Output[/align]
For each case,you should draw a rectangle with the width and height giving in the input.
after each case, you should a blank line.
[align=left]Sample Input[/align]
3 2
[align=left]Sample Output[/align]
+---+
| |
| |
+---+代码:
#include<stdio.h> int main() { int n,m; while(scanf("%d%d",&n,&m)!=EOF) { for(int i=1;i<=m+2;i++) { if(i==1||i==m+2) { printf("+"); for(int j=2;j<n+2;j++) printf("-"); printf("+\n"); } else { printf("|"); for(int j=2;j<n+2;j++) { printf(" "); } printf("|\n"); } } printf("\n"); } return 0; }
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