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[Codeforces677B]Vanya and Food Processor(模拟,数学)

2016-06-03 12:58 399 查看
题目链接:http://codeforces.com/contest/677/problem/B

题意:n个土豆,每个土豆高ai。现在有个加工机,最高能放h,每次能加工k。问需要多少次才能把土豆全加工完。

模拟就行了,加工次数用相除的结果,一个一个来会TLE

/*
━━━━━┒ギリギリ♂ eye!
┓┏┓┏┓┃キリキリ♂ mind!
┛┗┛┗┛┃\○/
┓┏┓┏┓┃ /
┛┗┛┗┛┃ノ)
┓┏┓┏┓┃
┛┗┛┗┛┃
┓┏┓┏┓┃
┛┗┛┗┛┃
┓┏┓┏┓┃
┛┗┛┗┛┃
┓┏┓┏┓┃
┃┃┃┃┃┃
┻┻┻┻┻┻
*/
#include <algorithm>
#include <iostream>
#include <iomanip>
#include <cstring>
#include <climits>
#include <complex>
#include <fstream>
#include <cassert>
#include <cstdio>
#include <bitset>
#include <vector>
#include <deque>
#include <queue>
#include <stack>
#include <ctime>
#include <set>
#include <map>
#include <cmath>
using namespace std;
#define fr first
#define sc second
#define cl clear
#define BUG puts("here!!!")
#define W(a) while(a--)
#define pb(a) push_back(a)
#define Rlf(a) scanf("%lf", &a);
#define Rint(a) scanf("%d", &a)
#define Rll(a) scanf("%I64d", &a)
#define Rs(a) scanf("%s", a)
#define Cin(a) cin >> a
#define FRead() freopen("in", "r", stdin)
#define FWrite() freopen("out", "w", stdout)
#define Rep(i, len) for(int i = 0; i < (len); i++)
#define For(i, a, len) for(int i = (a); i < (len); i++)
#define Cls(a) memset((a), 0, sizeof(a))
#define Clr(a, x) memset((a), (x), sizeof(a))
#define Full(a) memset((a), 0x7f7f, sizeof(a))
#define lrt rt << 1
#define rrt rt << 1 | 1
#define pi 3.14159265359
#define RT return
#define lowbit(x) x & (-x)
#define onenum(x) __builtin_popcount(x)
typedef long long LL;
typedef long double LD;
typedef unsigned long long ULL;
typedef pair<int, int> pii;
typedef pair<string, int> psi;
typedef map<string, int> msi;
typedef vector<int> vi;
typedef vector<LL> vl;
typedef vector<vl> vvl;
typedef vector<bool> vb;

const int maxn = 100100;
int n, h, k;
int a[maxn];

int main() {
// FRead();
while(~scanf("%d%d%d",&n,&h,&k)) {
For(i, 1, n+1) Rint(a[i]);
LL ret = 0;
int i = 1;
LL tmp = 0;
while(i <= n) {
while(i <= n && tmp + a[i] <= h) tmp += a[i++];
if(tmp < k) {
ret++;
tmp = 0;
}
else {
ret += tmp / k;
tmp %= k;
}
}
if(tmp > 0) ret++;
cout << ret << endl;
}
RT 0;
}
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