为什麽要判断k<m和K>m+1
2016-06-02 18:07
232 查看
Option Base 1
Dim anma() As Integer
Dim m As Byte, n As Byte
Private Sub Command1_Click()
Cls
Me.Font.Size = 30
m = 5: n = 6
ReDim anma(m, n)
Dim i As Integer, j As Integer
For i = 1 To m
For j = 1 To n
anma(i, j) = 10 + Int(Rnd() * 90)
Next j
Next i
For i = 1 To m
For j = 1 To n
Print anma(i, j); Spc(3);
Next j
Print
Next i
Dim row_max As Integer, column_max As Byte
For i = 1 To m
row_msx = anma(i, 1)
column_max = 1
For j = 2 To n
If anma(i, j) > row_man Then
row_max = anma(i, j)
column_max = j
End If
Next j
For k = 1 To m
If anma(k, column_max) < row_max Then
Exit For
End If
Next k
If k = m + 1 Then
Print "鞍点:" & i & "," & column_max
End If
Next i
End Sub
Dim anma() As Integer
Dim m As Byte, n As Byte
Private Sub Command1_Click()
Cls
Me.Font.Size = 30
m = 5: n = 6
ReDim anma(m, n)
Dim i As Integer, j As Integer
For i = 1 To m
For j = 1 To n
anma(i, j) = 10 + Int(Rnd() * 90)
Next j
Next i
For i = 1 To m
For j = 1 To n
Print anma(i, j); Spc(3);
Next j
Next i
Dim row_max As Integer, column_max As Byte
For i = 1 To m
row_msx = anma(i, 1)
column_max = 1
For j = 2 To n
If anma(i, j) > row_man Then
row_max = anma(i, j)
column_max = j
End If
Next j
For k = 1 To m
If anma(k, column_max) < row_max Then
Exit For
End If
Next k
If k = m + 1 Then
Print "鞍点:" & i & "," & column_max
End If
Next i
End Sub
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