UVA oj 10300 Ecological Premium（水题）

Ecological Premium

Input:  standard input

Output:  standard output

Time Limit:  1 second

Memory Limit:  32 MB

German farmers are given a premium depending on the conditions at their farmyard. Imagine the following simplified regulation: you know the size of each farmer's farmyard in square meters and the number of animals living at it. We won't make a difference between
different animals, although this is far from reality. Moreover you have information about the degree the farmer uses environment-friendly equipment and practices, expressed in a single integer greater than zero. The amount of money a farmer receives can be
calculated from these parameters as follows. First you need the space a single animal occupies at an average. This value (in square meters) is then multiplied by the parameter that stands for the farmer's environment-friendliness, resulting in the premium
a farmer is paid per animal he owns. To compute the final premium of a farmer just multiply this premium per animal with the number of animals the farmer owns.

Input

The first line of input contains a single positive integer  n (<20) , the number of test cases. Each test case starts with a line containing a single integer  f (0<f<20) , the number
of farmers in the test case. This line is followed by one line per farmer containing three positive integers each: the size of the farmyard in square meters, the number of animals he owns and the integer value that expresses the farmer’s environment-friendliness.
Input is terminated by end of file. No integer in the input is greater than 100000  or less than  0 .

Output

For each test case output one line containing a single integer that holds the summed burden for Germany's budget, which will always be a whole number. Do not output any blank lines.

Sample Input

Sample Output

38

86

7445
已知农场的面积和动物的数目。 
此外还知道农场主使用设备的环境友好等级。 
农场主得到的奖金可以由上面三个参数计算得出。 
首先获得每只动物平均占用的面积。 
然后这个值乘以环境友好度参数，得到的是一只动物得到的奖金。 
最后把上面的值乘以动物的数目，就可以得到农场主获得的奖金。 
奖金 = 农场的面积 / 动物的数目 * 环境友好等级
* 动物的数目 = 农场的面积 * 环境友好等级 

#include<cstdio>
using namespace std;

typedef long long ll;

int main()
{
ll a,b,c,sum;
int n,t;
scanf("%d",&t);
while(t--)
{
sum = 0;
scanf("%d",&n);
for(int i=0;i<n;i++)
{
scanf("%lld%lld%lld",&a,&b,&c);
sum += a*c;
}
printf("%d\n",sum);
}
return 0;
}