第12周 项目二
2016-05-31 19:17
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/* *Copyright (c)2016,烟台大学计算机与控制工程学院 *All rights reserved. *文件名称:main.cpp *作 者:肖雪 *完成日期:2016年5月31日 *版 本 号:v1.0 *问题描述:实现Time类中的运算符重载 */ #include <iostream> using namespace std; class CTime { private: unsigned short int hour; unsigned short int minute; unsigned short int second; public: CTime(int h=0,int m=0,int s=0); void setTime(int h,int m,int s); friend istream &operator>>(istream &in,CTime &t); friend ostream &operator<<(ostream &out,CTime t); bool operator > (CTime &t); bool operator < (CTime &t); bool operator >= (CTime &t); bool operator <= (CTime &t); bool operator == (CTime &t); bool operator != (CTime &t); CTime operator+(CTime &c); CTime operator-(CTime &c); CTime operator+(int s); CTime operator-(int s); CTime operator++(int); CTime &operator++(); CTime operator--(int); CTime &operator--(); CTime &operator+=(CTime &c); CTime &operator-=(CTime &c); CTime &operator+=(int s); CTime &operator-=(int s); }; CTime::CTime(int h,int m,int s) { hour=h; minute=m; second=s; } void CTime::setTime(int h,int m,int s) { hour=h; minute=m; second=s; } istream &operator>>(istream &in,CTime &t) { char ch1,ch2; while(1) { cout<<"请输入时间(hh:mm:ss) "; cin>>t.hour>>ch1>>t.minute>>ch2>>t.second; if (ch1==':' && ch2==':') if (t.hour>-1 && t.hour<24 && t.minute>-1 && t.minute<60 && t.second>-1 && t.second<60) break; cerr<<"时间格式不正确! 请重新输入\n"; } return cin; } ostream &operator<<(ostream &out,CTime t) { out<<t.hour<<':'<<t.minute<<':'<<t.second; return out; } bool CTime::operator > (CTime &t) { if (hour>t.hour) return true; if (hour<t.hour) return false; if (minute>t.minute) return true; if (minute<t.minute) return false; if (second>t.second) return true; return false; } bool CTime::operator < (CTime &t) { if (hour<t.hour) return true; if (hour>t.hour) return false; if (minute<t.minute) return true; if (minute>t.minute) return false; if (second<t.second) return true; return false; } bool CTime::operator == (CTime &t) { if (*this<t || *this>t) return false; return true; } bool CTime::operator != (CTime &t) { if (*this==t) return false; return true; } bool CTime::operator >= (CTime &t) { if (*this<t) return false; return true; } bool CTime::operator <= (CTime &t) { if (*this>t) return false; return true; } CTime CTime::operator + (CTime &t) { int h,m,s; s=second+t.second; m=minute+t.minute; h=hour+t.hour; if (s>59) { s-=60; m++; } if (m>59) { m-=60; h++; } while (h>23) h-=24; CTime t0(h,m,s); return t0; } CTime CTime::operator+(int s) { int ss=s%60; int mm=(s/60)%60; int hh=s/3600; CTime t0(hh,mm,ss); return *this+t0; } CTime CTime::operator - (CTime &t) { int h,m,s; s=second-t.second; m=minute-t.minute; h=hour-t.hour; if (s<0) { s+=60; m--; } if (m<0) { m+=60; h--; } while (h<0) h+=24; CTime t0(h,m,s); return t0; } CTime CTime::operator-(int s) { int ss=s%60; int mm=(s/60)%60; int hh=s/3600; CTime t0(hh,mm,ss); return *this-t0; } CTime CTime::operator++(int) { CTime t=*this; *this=*this+1; return t; } CTime &CTime::operator++() { *this=*this+1; return *this; } CTime CTime::operator--(int) { CTime t=*this; *this=*this-1; return t; } CTime &CTime::operator--() { *this=*this-1; return *this; } CTime &CTime::operator+=(CTime &c) { *this=*this+c; return *this; } CTime &CTime::operator-=(CTime &c) { *this=*this-c; return *this; } CTime &CTime::operator+=(int s) { *this=*this+s; return *this; } CTime &CTime::operator-=(int s) { *this=*this-s; return *this; } int main() { CTime t1,t2,t; cout<<"t1为:"; cin>>t1; cout<<"t2为:"; cin>>t2; cout<<"下面比较两个时间大小:\n"; if (t1>t2) cout<<"t1>t2"<<endl; if (t1<t2) cout<<"t1<t2"<<endl; if (t1==t2) cout<<"t1=t2"<<endl; if (t1!=t2) cout<<"t1≠t2"<<endl; if (t1>=t2) cout<<"t1≥t2"<<endl; if (t1<=t2) cout<<"t1≤t2"<<endl; cout<<endl; cout<<"t1= "<<t1<<endl; cout<<"t2= "<<t2<<endl; cout<<"t=t1++"<<endl; t=t1++; cout<<"t= "<<t<<" t1= "<<t1<<endl; cout<<"t=++t1"<<endl; t=++t1; cout<<"t= "<<t<<" t1= "<<t1<<endl; cout<<"t1+t2= "<<t1+t2<<endl; cout<<"t1-t2= "<<t1-t2<<endl; cout<<"t1+2000= "<<t1+2000<<endl; cout<<"t1-5000= "<<t1-5000<<endl; return 0; }
学习心得:重载运算符"+"和"-"实现时间推后和提前若干分钟;
重载运算符"++"和"--"实现当前时间推后和提前1小时;
重载运算符">"、"<"、"=="来判断两个时间之间大于、小于、等于以及不等于的关系。
运算符重载不能改变运算符的逻辑特性
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