【SWUSTOJ】1001: A+B again!!

 1001: A+B again!!

Description

Your task is to calculate the sum of some integers.

Input

Input contains multiple test cases, and one case one line. Each case starts with an integer N( 0 < N<=500 ), and then N integers follow in the same line.

Output

For each test case you should output the sum of N integers in one line, and with one line of output for each line in input.

4 1 2 3 4
5 1 2 3 4 5

10
15

Hint

提供一个参考程序：

C语言：
#include"cstdio"  ///也可以使用 < >
int main()
{
int n,x,sum;
while(scanf("%d", &n) != EOF)  /// EOF: end of file  文件结束标志
{
sum = 0;
while(n--)
{
scanf("%d", &x);
sum += x;
}
printf("%d\n", sum);
}
return 0;
}

C++:
#include"iostream"  ///也可以使用 < >
using namespace std;
int main()
{
int n,x,sum;
while(cin >> n)
{
sum = 0;
while(n--)
{
cin >> x;
sum += x;
}
cout << sum << endl;
}
return 0;
}

Source

#include<iostream>
using namespace std;
int main()
{
int n,a;
while(cin>>n)
{int sum=0;
while(n)
{
cin>>a;
sum+=a;
n--;
}
cout<<sum<<endl;
}

return 0;
}