HDU 2602 Bone Collector

题目链接：http://acm.hdu.edu.cn/showproblem.php?pid=2602

Bone Collector

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)

Total Submission(s): 48219    Accepted Submission(s): 20113

Problem Description

Many years ago , in Teddy’s hometown there was a man who was called “Bone Collector”. This man like to collect varies of bones , such as dog’s , cow’s , also he went to the grave …

The bone collector had a big bag with a volume of V ,and along his trip of collecting there are a lot of bones , obviously , different bone has different value and different volume, now given the each bone’s value along his trip , can you calculate out the
maximum of the total value the bone collector can get ?

Input

The first line contain a integer T , the number of cases.

Followed by T cases , each case three lines , the first line contain two integer N , V, (N <= 1000 , V <= 1000 )representing the number of bones and the volume of his bag. And the second line contain N integers representing the value of each bone. The third
line contain N integers representing the volume of each bone.

Output

One integer per line representing the maximum of the total value (this number will be less than 231).

Sample Input

1
5 10
1 2 3 4 5
5 4 3 2 1

 

Sample Output

14

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Author

Teddy

Source

HDU 1st “Vegetable-Birds Cup” Programming
Open Contest

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比较经典的01背包。不多解释，这里采用滚动数组优化空间复杂度。

附上AC代码：

#include <bits/stdc++.h>
//#pragma comment(linker, "/STACK:102400000, 102400000")
using namespace std;
const int maxn = 1005;
int dp[maxn];
int c[maxn], w[maxn];
int n, v;

int main(){
#ifdef LOCAL
freopen("input.txt", "r", stdin);
freopen("output.txt", "w", stdout);
#endif
int T;
scanf("%d", &T);
while (T--){
scanf("%d%d", &n, &v);
for (int i=0; i<n; ++i)
scanf("%d", w+i);
for (int i=0; i<n; ++i)
scanf("%d", c+i);
memset(dp, 0, sizeof(int)*(v+1));
for (int i=0; i<n; ++i)
for (int j=v; j>=c[i]; --j)
dp[j] = max(dp[j], dp[j-c[i]]+w[i]);
printf("%d\n", dp[v]);
}
return 0;
}