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leetcode-101

2016-05-25 00:12 337 查看
题目:

Given a binary tree, check whether it is a mirror of itself (ie, symmetric around its center).

For example, this binary tree is symmetric:
1
/ \
2   2
/ \ / \
3  4 4  3


But the following is not:

1
/ \
2   2
\   \
3    3


代码:

/**

 * Definition for a binary tree node.

 * public class TreeNode {

 *     int val;

 *     TreeNode left;

 *     TreeNode right;;

 *     TreeNode(int x) { val = x; }

 * }

 */

public class Solution {

   

  public boolean helper(TreeNode left, TreeNode right){
if(left == null || right == null)
{
if(left == right)
return true;
else
return false;
}
if(left.val != right.val)
return false;
else
return helper(left.left,right.right) && helper(left.right,right.left);
}

public boolean isSymmetric(TreeNode root) {

if(root == null)
return true;
else
return helper(root.left,root.right);
}

}
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