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负数运算符的重载(2)

2016-05-23 12:56 411 查看

*Copyright (c) 2014,烟台大学计算机学院

*All right reserved.

*文件名称:test.cpp

*作 者:韩双志

*完成日期:2016年5月23日

*版本号:v1.0

*

*问题描述:请用类的友元函数,而不是成员函数,再次完成上面提及的运算符的重载;

*输入描述:无

*输出描述:输出运算符重载后的结果

/*

#include<iostream>

#include<Cmath>

using namespace std;

class Complex

{

public:

Complex(){real=0;imag=0;}

Complex(double r,double i){real=r; imag=i;}

friend Complex operator+(Complex &c1,Complex &c2);

friend Complex operator-(Complex &c1,Complex &c2);

friend Complex operator*(Complex &c1,Complex &c2);

friend Complex operator/(Complex &c1,Complex &c2);

void display();

private:

double real;

double imag;

};

Complex operator+(Complex &c1,Complex &c2)

{

Complex c;

c.real=c1.real+c2.real;

c.imag=c1.imag+c2.imag;

return c;

}

Complex operator-(Complex &c1,Complex &c2)

{

Complex c;

c.real=c1.real-c2.real;

c.imag=c1.imag-c2.imag;

return c;

}

Complex operator*(Complex &c1,Complex &c2)

{

Complex c;

c.real=c1.real*c2.real-c1.imag*c2.imag;

c.imag=c1.imag*c2.real+c1.real*c2.imag;

return c;

}

Complex operator/(Complex &c1,Complex &c2)

{

Complex c;

c.real=(c1.real*c2.real+c1.imag*c2.imag)/(c2.real*c2.real+c2.imag*c2.imag);

c.imag=(c1.imag*c2.real-c1.real*c2.imag)/(c2.real*c2.real+c2.imag*c2.imag);

return c;

}

void Complex::display()

{

cout<<"("<<real<<","<<imag<<"i)"<<endl;

}

int main()

{

Complex c1(3,4),c2(5,-10),c3;

cout<<"c1=";

c1.display();

cout<<"c2=";

c2.display();

c3=c1+c2;

cout<<"c1+c2=";

c3.display();

c3=c1-c2;

cout<<"c1-c2=";

c3.display();

c3=c1*c2;

cout<<"c1*c2=";

c3.display();

c3=c1/c2;

cout<<"c1/c2=";

c3.display();

return 0;

}

*/

运行结果:



知识点总结

运算符的重载,友元函数的实现、

学习心得

了解了运算符的重载,友员函数的实现
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