您的位置:首页 > 其它

LeetCode 350. Intersection of Two Arrays II

2016-05-22 08:22 507 查看
Given two arrays, write a function to compute their intersection.

Example:

Given nums1 =
[1, 2, 2, 1]
, nums2 =
[2, 2]
, return
[2, 2]
.

Note:

Each element in the result should appear as many times as it shows in both arrays.
The result can be in any order.

class Solution {
public:
vector<int> intersect(vector<int>& nums1, vector<int>& nums2) {
if(nums1.size() == 0 || nums2.size() == 0) return {};
sort(nums1.begin(), nums1.end());
sort(nums2.begin(), nums2.end());

int i = 0, j = 0;
vector<int> res;
while(i < nums1.size() && j < nums2.size()) {
if(nums1[i] == nums2[j]) {
res.push_back(nums1[i]);
i++;
j++;
} else if(nums1[i] < nums2[j]) {
i++;
} else j++;
}
return res;
}
};
内容来自用户分享和网络整理,不保证内容的准确性,如有侵权内容,可联系管理员处理 点击这里给我发消息
标签: