您的位置:首页 > 其它

110. Balanced Binary Tree

2016-05-19 11:12 169 查看

Balanced Binary Tree

判断是不是平衡二叉树

代码

public class Solution {

private int helper(TreeNode root, int height){
if (root == null)
{
return height;
}

int leftTree = helper(root.left, height + 1);
int rightTree = helper(root.right, height + 1);
if (leftTree < 0 || rightTree < 0 || Math.abs(leftTree - rightTree) > 1)
{
return -1;
}

return Math.max(leftTree, rightTree);
}
public boolean isBalanced(TreeNode root) {
return helper(root, 0) >= 0;
}
}
内容来自用户分享和网络整理,不保证内容的准确性,如有侵权内容,可联系管理员处理 点击这里给我发消息
标签: