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hdu1054Strategic Game&&hdu1150Machine Schedule(最小顶点覆盖)

2016-05-18 18:25 302 查看
题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1054

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1150

在二分图中选取最少的点,使每一条边至少与一个点相关联,最小顶点覆盖 = 最大匹配(定理)

1054代码:

#include <cstdio>
#include <vector>
#include <cstring>

using namespace std;

const int maxn = 1500;
vector<int> g[maxn + 5];
int match[maxn + 5];
int book[maxn + 5];
int ans;
bool dfs(int u)

{
for(int i = 0; i < g[u].size(); ++i)
{
int v = g[u][i];
if(!book[v])
{
book[v] = true;
if(match[v] == -1 || dfs(match[v]))
{
match[v] = u;
// match[u] = v;
return true;
}
}
}
return false;
}
int main()

{
int n;
while(~scanf("%d",&n))
{
for(int i = 0; i < n; ++i)
g[i].clear();
for(int i = 0; i < n; ++i)
{
int u,v;
int num;
scanf("%d:(%d)",&u,&num);
if(num)
{
while(num--)
{
scanf("%d",&v);
g[u].push_back(v);
g[v].push_back(u);
}
}
}
memset(match,-1,sizeof(match));
ans = 0;
for(int i = 0; i < n; ++i)
{
memset(book,0,sizeof(book));
if(dfs(i))
ans++;
}
printf("%d\n",ans / 2);
}
return 0;
}


1150代码:

#include <cstdio>
#include <cstring>

int n,m,k;
int a[205][205];
int match[205];
int book[205];

int dfs(int u)

{
for(int i = 1;i <= m;++i)
{
int v = a[u][i];

if(v && !book[i])
{
book[i] = 1;
if(match[i] == -1 || dfs(match[i]))
{
match[i] = u;
return 1;
}
}

}
return 0;
}
int main()

{
while(~scanf("%d",&n),n)
{
scanf("%d%d",&m,&k);
memset(a,0,sizeof(a));
for(int i = 0;i < k;++i)
{
int num,u,v;
scanf("%d%d%d",&num,&u,&v);
a[u][v] = 1;
//a[v][u] = 1;
}
memset(match,-1,sizeof(match));
int ans = 0;
for(int i = 1;i <= n;++i)
{
memset(book,0,sizeof(book));
ans += dfs(i);
}
printf("%d\n",ans);
}
return 0;
}
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