Java--银行账户存取款线程设计1（交互线程）

线程之间可能无关，也可能交互。

而线程的同步机制并发执行的交互线程间存在与时间有关的错误。

public class account {

private String name;
private double balance;
public account(String name) {
this.name = name;
this.balance=0;
}
public String getName() {
return name;
}
public double getBalance() {
return balance;
}
//
public void put(double value){
if(value>0){
this.balance=this.balance+value;
}

}
public double  get(double value){
if(value>0){
if(value<=balance){
this.balance=this.balance-value;
}else{
value=this.balance;
this.balance=0;
}

}
return value;
}
}

public class save extends Thread{
private account a;
private double value;

public save(account a, double value) {
this.a = a;
this.value = value;
}

public void run() {
double b=a.getBalance();
a.put(value);
System.out.println(a.getName()+"账户，现有"+b+",存入"
+value+"，余额"+a.getBalance());
}

}

public class fetch extends Thread{
private account a;
private double value;

public fetch(account a, double value) {
this.a = a;
this.value = value;
}

public void run() {
double b=a.getBalance();
System.out.println(a.getName()+"账户，现有"+b+",取出"
+a.get(value)+"，余额"+a.getBalance());
}
}

public class bank {

public static void main(String[] args) {

//      account a1=new account("wang");
//      save s1=new save(a1,100);
//      save s1=new save(new account("wang"),100);
//      s1.start();
account a1=new account("wang");
new save(a1,100).start();
new save(a1,200).start();
new fetch(a1,300).start();

new save(new account("xu"),100).start();
}

}

运行结果1：

wang账户，现有0.0,存入100.0，余额100.0

wang账户，现有100.0,取出100.0，余额0.0

wang账户，现有0.0,存入200.0，余额200.0

xu账户，现有0.0,存入100.0，余额100.0

运行结果2：

wang账户，现有0.0,存入100.0，余额100.0

wang账户，现有100.0,存入200.0，余额300.0

xu账户，现有0.0,存入100.0，余额100.0

wang账户，现有300.0,取出300.0，余额0.0

由运行结果可以看出，线程很乱