Flea travel
2016-05-16 22:09
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Description
Can you imagine our life if we removed all zeros from it? For sure we will have many problems.
In this problem we will have a simple example if we removed all zeros from our life, it's the addition operation. Let's assume you are given this equation a + b = c, where a and b are
positive integers, and c is the sum of a and b. Now let's remove
all zeros from this equation. Will the equation remain correct after removing all zeros?
For example if the equation is 101 + 102 = 203, if we removed all zeros it will be 11 + 12 = 23 which is still a correct equation.
But if the equation is 105 + 106 = 211, if we removed all zeros it will be 15 + 16 = 211 which is not a correct equation.
Input
The input will consist of two lines, the first line will contain the integer a, and the second line will contain the integer b which
are in the equation as described above (1 ≤ a, b ≤ 109). There won't be any leading zeros in both. The value of c should
be calculated as c = a + b.
Output
The output will be just one line, you should print "YES" if the equation will remain correct after removing all zeros, and print "NO" otherwise.
Sample Input
Input
Output
Input
Output
NO
题意:
输入两个数字a b,求出其和c。将a,b,c中的零去掉,如果还满足a+b=c,则输出YES,否则输出NO
编写一个函数exzero()求a,b去掉0后的结果
代码如下
#include<stdio.h>
#include<string.h>
#include<algorithm>
using namespace std;
int exzero(int a)
{
int x,m;
x=0;m=1;
while(a)
{
if(a%10!=0)
{
x+=a%10*m;
m*=10;
}
a=a/10;
}
return x;
}
int main()
{
int a,b;
scanf("%d%d",&a,&b);
int c=a+b;
if(exzero(a)+exzero(b)==exzero(c))
printf("YES\n");
else
printf("NO\n");
}
Can you imagine our life if we removed all zeros from it? For sure we will have many problems.
In this problem we will have a simple example if we removed all zeros from our life, it's the addition operation. Let's assume you are given this equation a + b = c, where a and b are
positive integers, and c is the sum of a and b. Now let's remove
all zeros from this equation. Will the equation remain correct after removing all zeros?
For example if the equation is 101 + 102 = 203, if we removed all zeros it will be 11 + 12 = 23 which is still a correct equation.
But if the equation is 105 + 106 = 211, if we removed all zeros it will be 15 + 16 = 211 which is not a correct equation.
Input
The input will consist of two lines, the first line will contain the integer a, and the second line will contain the integer b which
are in the equation as described above (1 ≤ a, b ≤ 109). There won't be any leading zeros in both. The value of c should
be calculated as c = a + b.
Output
The output will be just one line, you should print "YES" if the equation will remain correct after removing all zeros, and print "NO" otherwise.
Sample Input
Input
101 102
Output
YES
Input
105 106
Output
NO
题意:
输入两个数字a b,求出其和c。将a,b,c中的零去掉,如果还满足a+b=c,则输出YES,否则输出NO
编写一个函数exzero()求a,b去掉0后的结果
代码如下
#include<stdio.h>
#include<string.h>
#include<algorithm>
using namespace std;
int exzero(int a)
{
int x,m;
x=0;m=1;
while(a)
{
if(a%10!=0)
{
x+=a%10*m;
m*=10;
}
a=a/10;
}
return x;
}
int main()
{
int a,b;
scanf("%d%d",&a,&b);
int c=a+b;
if(exzero(a)+exzero(b)==exzero(c))
printf("YES\n");
else
printf("NO\n");
}
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