如何取一个表的分组中时间最晚的一条记录？

SELECT a.TruckOrder,a.AddrType ,a.OpeaterBy ,c.DeptName, b.Driver+'-'+CONVERT(VARCHAR(16),e.OpeaterDT,121)AS DOpeaterDT, b.Driver+'-'+CONVERT(VARCHAR(16),f.OpeaterDT,121)AS COpeaterDT, b.Driver+'-'+CONVERT(VARCHAR(16),g.OpeaterDT,121)AS LOpeaterDT, b.Driver+'-'+CONVERT(VARCHAR(16),h.OpeaterDT,121)AS HOpeaterDT, b.Driver,b.TransType,CONVERT(VARCHAR(16),b.TruckDT,121)AS TruckDT,b.TruckNo,b.TruckModel INTO #TruckWay FROM dbo.T_TruckWay AS a JOIN dbo.T_TruckOrder AS b ON a.TruckOrder=b.TruckOrder AND b.CFMFlag='Y' AND b.AuctionStatus='Y' JOIN BAS_DepartMent AS c ON b.DeptCode=c.DeptCode JOIN (SELECT TruckOrder,MAX(OpeaterDT)AS OpeaterDT FROM T_TruckWay GROUP BY TruckOrder) AS d ON a.TruckOrder=d.TruckOrder AND a.OpeaterDT=d.OpeaterDT LEFT JOIN T_TruckWay AS e ON a.TruckOrder=e.TruckOrder AND e.AddrType=3 LEFT JOIN T_TruckWay AS f ON a.TruckOrder=f.TruckOrder AND f.AddrType=4 LEFT JOIN T_TruckWay AS g ON a.TruckOrder=g.TruckOrder AND g.AddrType=5 LEFT JOIN T_TruckWay AS h ON a.TruckOrder=h.TruckOrder AND h.AddrType=6 SELECT * FROM #TruckWay SELECT COUNT(1) AS total FROM #TruckWay

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