PAT乙级1012-D进制的A+B (20)

//D进制的A+B (20)
#include<iostream>
#include<stdlib.h>
#include<string>

using namespace std;
string conversion_number(int sum, int D )
{
string str = "" ;  //用string类型返回
while (sum )  //模除求得进制
{
str = ( char)(sum %D + '0') + str;
sum /= D ;
}
return str;
}
int main()
{
int A = 0, B = 0;
int D = 0;
cout << "请输入A，B，D的值" << endl;;
cin >> A >> B >> D;

int sum = A + B;
string str = conversion_number(sum, D);
cout << str;

system( "pause");
return 0;
}