Leetcode 221 Maximal Square

Given a 2D binary matrix filled with 0's and 1's, find the largest square containing all 1's and return its area.

For example, given the following matrix:

1 0 1 0 0
1 0 1 1 1
1 1 1 1 1
1 0 0 1 0

Return 4.

a[i][j]表示在以matrix[i][j]为右下角的最大正方形边长

转移方程：

如果当前位置为1，则：

a[i][j] = min(a[i-1][j-1],a[i-1][j],a[i][j-1]) + 1

否则为0

这边开了一个比matrix大一圈的a数组，来避免越界以及第一行和列的拷贝操作

class Solution(object):
def maximalSquare(self, matrix):
"""
:type matrix: List[List[str]]
:rtype: int
"""
if not matrix: return 0
m, n, t = len(matrix),len(matrix[0]), 0
a = [[0 for i in range(n+1)] for i in range(m+1)]
for i in range(1,m+1):
for j in range(1,n+1):
if matrix[i-1][j-1] == '1':
a[i][j] = min(a[i-1][j-1],a[i-1][j],a[i][j-1]) + 1t = max(t,a[i][j])
return t*t