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洗牌算法

2016-05-08 15:59 423 查看
题目要求: 用计算机模拟洗牌(不包括大小王),分发给四个玩家并将四个玩家的牌显示出来。

思路:i从0~51遍历,每次产生i到52之间的随机数k(i<k<52),交换第i 和第k张牌。

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;

namespace ConsoleApplication1
{
class Program
{
static void Main(string[] args)
{
int i, j;
Random Rnd = new Random();
int k;
int[] Card = new int[52];
int[,] Player = new int[4, 13];
for (i = 0; i < 4; i++)
{
for (j = 0; j < 13; j++)
{
Card[i * 13 + j] = (i + 1) * 100 + j + 1;
}
}
Console.Write("Please input times:");
string s = Console.ReadLine();
int times = Convert.ToInt32(s);
for (j = 1; j <= times; j++)
{
for (i = 0; i < 52; i++)
{
k = Rnd.Next(51 - i + 1) + i;
int temp = Card[i];
Card[i] = Card[k];
Card[k] = temp;
}
}
k = 0;
for (j = 0; j < 13; j++)
{
for (i = 0; i < 4; i++)
{
Player[i, j] = Card[k++];
}
}
for (i = 0; i < 4; i++)
{
Console.WriteLine("Player{0}:", i + 1);
for (j = 0; j < 13; j++)
{
k = (int)Player[i, j] / 100;
switch (k)
{
case 1:
s = Convert.ToString("红桃");
break;
case 2:
s = Convert.ToString("方片");
break;
case 3:
s = Convert.ToString("梅花");
break;
case 4:
s = Convert.ToString("黑桃");
break;
}
k = Player[i, j] % 100;
switch (k)
{
case 1:
s = s + "A";
break;
case 11:
s = s + "J";
break;
case 12:
s = s + "Q";
break;
case 13:
s = s + "K";
break;
default:
s = s + Convert.ToString(k);
break;
}
Console.Write(s);
if (j < 12)
Console.Write(", ");
else
Console.WriteLine(" ");
}
}
Console.Read();
}
}
}


注:

101,102,103...113 分别表示红桃A,红桃2,...红桃K

201,202,203...213分别表示方块A,方块2,...方块K

301,302,303...313 分别表示梅花A,梅花2,...梅花K

401,402,403...413分别表示黑桃A,黑桃2,...黑桃K
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