矩形相关操作

题目描述

如下结构用来存储图像屏幕上的对象信息。

struct point {int x, y;};

struct rectangle{struct point upper_left, lower_right;};

编写函数，要求可以在rectangle结构变量r上执行以下操作，且r作为实际参数传递

1.计算r的面积

2.计算r的中心，并且以此中心作为point值返回，如果中心的x或y坐标不为整数，取整数值

3.确定点p是否在r内，返回1或0.(p是struct point类型的另外一个实际参数)


[b]输入描述
[/b]

[b]输入分两行
第一行输入四个整数，分别代表矩形的左上角和右下角坐标
第二行输入两个整数，代表某个点的坐标
[/b]

[b]输出描述
[/b]

输出分三行
Area of r is 面积值
Center of r is <中心点坐标>
Point <输入点的坐标> is [not] in r

代码

<span style="font-size:14px;">#include<iostream>
using namespace std;
struct point
{
int x, y;
};
struct rectangle
{
struct point upper_left, lower_right;
};
int mj(int x1, int y1, int x2, int y2)
{
int s;
s = (x2 - x1)*(y1 - y2);
return s;
}
struct point u(int x1, int y1, int x2, int y2)
{
point p;
p.x = (x1 + x2) / 2; p.y = (y1 + y2) / 2;
return p;
}
int r(int x1, int y1, int x2, int y2, int x3, int y3)
{
if ((x1 <= x3) && (x3 <= x2) && (y1 >= y3) && (y3 >= y2))
return 1;
else
return 0;
}
int main()
{
int s,a;
int x1, x2, y1, y2, x3, y3;
struct point b;
cin >> x1 >> y1 >> x2 >> y2;
cin >> x3 >> y3;
struct point upper_left = { x1, y1 };
struct point lower_right = { x2, y2 };
s = mj(x1, y1, x2, y2);
b=u(x1, y1, x2, y2);
cout << "Area of r is " << s << endl;
cout << "Center of r is <" << b.x<<","<<b.y << ">" << endl;
a = r(x1, y1, x2, y2, x3, y3);
if (a ==1)
cout << "Point " << "<" << x3 << "," << y3 << "> is in r";
else
cout << "Point " << "<" << x3 << "," << y3 << "> is not in r";
return 0;
}</span>
是struct oint类型的另外一个实际参数)