Remove Duplicates from Sorted Array

Given a sorted array, remove the duplicates in place such that each element appear only once and return the new length.

Do not allocate extra space for another array, you must do this in place with constant memory.

For example,

Given input array nums = 

[1,1,2]

,

Your function should return length = 

2

, with the first two elements of nums being 

1

 and 

2

 respectively.
It doesn't matter what you leave beyond the new length.

class Solution {
public:
int removeDuplicates(vector<int>& nums) {
int i;
int n = nums.size();
if(n < 2) return n;
int j = 0;
for (i = 1; i < n; i++){
if(nums[i] != nums[j]){
nums[++j] = nums[i];
}
}
return j+1;
}
};自己第一次编辑的时候，函数直接返回的是j，即return j 然后必然的没有通过测试，结果让我发现了，如果数组里面所有的数字都是一样的这种测试情况下，根本就跳不进去if条件语句，j的值一直是0，所以这一种情况下应该返回的是1，还有就是数组的个数和数组下标之间是差一个1的，所以总的来说，函数返回值应该是j+1，即return j+1.