mysql查询某月每一天的数据总和

原文地址：http://bbs.chinaunix.net/thread-4112061-1-1.html

查当年的12个月的：

SELECT COUNT(*),CONCAT(YEAR(attack_date),'-',MONTH(attack_date)) FROM w3a_log_monitor_attack WHERE attack_user='192.168.31.135' GROUP BY CONCAT(YEAR(attack_date),'-',MONTH(attack_date))

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查当月的30/31天的：

SELECT COUNT(*),CONCAT(YEAR(attack_date),'-',MONTH(attack_date),'-',DAYOFMONTH(attack_date)) FROM w3a_log_monitor_attack WHERE attack_user='192.168.31.135' and attack_date>DATE_SUB(CURDATE(),INTERVAL DAY(CURDATE())-1 DAY) GROUP BY CONCAT(YEAR(attack_date),'-',MONTH(attack_date),'-',DAYOFMONTH(attack_date))

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查小时的（24小时）:

SELECT COUNT(*),HOUR(attack_date) FROM w3a_log_monitor_attack WHERE attack_user='192.168.31.135' and attack_date > DATE(NOW()) GROUP BY HOUR(attack_date) ;