您的位置:首页 > 其它

leetcode 136 single number

2016-05-03 10:00 483 查看
Given an array of integers, every element appears twice except for one. Find that single one.

Note:

Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory?

Subscribe to see which companies asked this question

class Solution {
public:
int singleNumber(vector<int>& nums) {
int answer=nums[0];
for(unsigned long i=1;i!=nums.size();++i)
answer=answer^nums[i];
return answer;
}
};
内容来自用户分享和网络整理,不保证内容的准确性,如有侵权内容,可联系管理员处理 点击这里给我发消息
标签: