leetcode58:Length of last word
2016-05-02 13:20
393 查看
package com.leetcode;
public class Solution58 {
public static int lastWordLength(String str){
if( str.lastIndexOf(' ') != -1)
return str.trim().length()-str.trim().lastIndexOf(' ')-1;
else
return str.length();
}
public static void main(String[] args) {
// TODO Auto-generated method stub
String str="a ";
System.out.println(Solution58.lastWordLength(str));
}
}
相关文章推荐
- 使用HTTPURLConnection模拟登陆,爬取网页内容
- HDU1501zipper
- Android群英传笔记——第十二章:Android5.X 新特性详解,Material Design UI的新体验
- 移动端 js 弹出层内容滚动的时候,不影响body的滚动条处理
- 轻量级自动化运维工具ansible之一:初步介绍及简单运用
- NYOJ - 24 素数距离问题
- 设置JDBC数据库连接池
- fatal error: wiring.h: No such file or directory
- 3. Longest Substring Without Repeating Characters
- c++ auto_ptrs
- CodeForces 668B Little Artem and Dance
- zookeeper原理(转)
- Property’s synthesized getter follows Cocoa naming
- CodeForces 668B Little Artem and Dance
- HDU 1158 Employment Planning
- 666
- C# Queue源码剖析
- Spark Streaming 新手指南(原始文章已经发布表在IBM Developworks)
- Tab的改造
- CodeForces 667A Pouring Rain