1035. Password (20)

To prepare for PAT, the judge sometimes has to generate random passwords for the users. The problem is that there are always some confusing passwords since it is hard to distinguish 1 (one) from l (L in lowercase), or 0 (zero) from O (o in uppercase). One solution
is to replace 1 (one) by @, 0 (zero) by %, l by L, and O by o. Now it is your job to write a program to check the accounts generated by the judge, and to help the juge modify the confusing passwords.

Input Specification:

Each input file contains one test case. Each case contains a positive integer N (<= 1000), followed by N lines of accounts. Each account consists of a user name and a password, both are strings of no more than 10 characters with no space.

Output Specification:

For each test case, first print the number M of accounts that have been modified, then print in the following M lines the modified accounts info, that is, the user names and the corresponding modified passwords. The accounts must be printed in the same order
as they are read in. If no account is modified, print in one line "There are N accounts and no account is modified" where N is the total number of accounts. However, if N is one, you must print "There is 1 account and no account is modified" instead.

IDEA

1.一个int Modify(string &s); 函数解决问题：边遍历边修改，返回是否进行了修改

2.如果password被修改了，则count++，并存入vec；

3.输出vec中存入的数据

CODE

#include<iostream>
#include<cstring>
#include<vector>
using namespace std;
struct Stu{
string username;
string password;
};
int Modify(string &s){
int len=s.length();
int flag=0;
for(int i=0;i<len;i++){
switch(s[i]){
case '1':s[i]='@';flag=1;break;
case '0':s[i]='%';flag=1;break;
case 'l':s[i]='L';flag=1;break;
case 'O':s[i]='o';flag=1;break;
}
}
if(flag){
return 1;//需要修改
}
return 0;
}
int main(){
int n;
cin>>n;
int count=0;
vector<Stu> vec;
for(int i=0;i<n;i++){
Stu stu;
cin>>stu.username>>stu.password;
if(Modify(stu.password)){
count++;
vec.push_back(stu);
}
}
if(count==0){
if(n==1){
cout<<"There is "<<n<<" account and no account is modified";
}else{
cout<<"There are "<<n<<" accounts and no account is modified";
}
}else{
cout<<count<<endl;
for(int i=0;i<vec.size();i++){
cout<<vec[i].username<<" "<<vec[i].password<<endl;
}
}
return 0;
}